GROUP BY TYEAR, GNUM
select 2013,trunc(sysdate)-125 from dual union all
select 2015,trunc(sysdate)-104 from dual union all
create table test_num
需要查询出某个客户某一年那些天是有连续办理过业务
select 2014,trunc(sysdate)-002 from dual union all

需求说明：
FROM (SELECT A.*, A.TDATE - ROWNUM AS GNUM
ORDER BY TYEAR, MIN(TDATE)
select 2015,trunc(sysdate)-099 from dual union all
select 2015,trunc(sysdate)-102 from dual union all

select 2013,trunc(sysdate)-124 from dual union all

select 2013,trunc(sysdate)-121 from dual union all
tdate date);

FROM (SELECT * FROM TEST_NUM ORDER BY TYEAR, TDATE) A)
select 2014,trunc(sysdate)-004 from dual union all
(tyear number,
创建表：
select 2015,trunc(sysdate)-100 from dual union all
select 2015,trunc(sysdate)-101 from dual union all
SELECT TYEAR, MIN(TDATE) AS STARTDATE, MAX(TDATE), COUNT(TYEAR) AS ENDNUM
select 2015,trunc(sysdate)-105 from dual;
select 2014,trunc(sysdate)-003 from dual union all
insert into test_num

写SQL:

复制代码 代码如下:

实现SQL如下：
select 2013,trunc(sysdate)-127 from dual union all
select 2014,trunc(sysdate)-009 from dual union all

测试数据：
select 2014,trunc(sysdate)-007 from dual union all
select 2014,trunc(sysdate)-008 from dual union all

复制代码 代码如下:

select 2014,trunc(sysdate)-005 from dual union all
select 2014,trunc(sysdate)-1 from dual union all
select 2013,trunc(sysdate)-122 from dual union all
select 2013,trunc(sysdate)-120 from dual union all