NumberFormatInfo info3 = info1.NumberFormat;
            }
      if ((code1 != TypeCode.String) && (code1 != TypeCode.Char))

复制代码 代码如下:

{
      }
            else
}

        bolResult=false;
    }
            case TypeCode.Char:
}

      }
            flag1 = true;
    try
            return double.TryParse(Value, NumberStyles.Any, info2, out Result);
{
            return Utils.IsNumericTypeCode(code1);
                  ch1 = char.ToLower(Value[num1 + 1], CultureInfo.InvariantCulture);
    Regex objNotNumberPattern=new Regex("[^0-9.-]");
        {

方法：首先需要添加Visualbasic.runtime的引用
            case TypeCode.Boolean:

a)

代码中Using Microsoft.visualbasic;
            case TypeCode.Int64:
            {
    bool haveDot = false;
        {
                        i64Value = Convert.ToInt64(text1, 8);

复制代码 代码如下:

    }
        !objTwoDotPattern.IsMatch(strNumber) &&

return !objNotNumberPattern.IsMatch(strNumber) &&
            case TypeCode.Decimal:
            if ((ch1 != ' ') && (ch1 != '/u3000'))
    for (int i = 0; i < inString.Length; i++)
// return Utils.IsNumericTypeCode(code1);
      CultureInfo info1 = Utils.GetCultureInfo();
            case TypeCode.UInt64:
    Regex objNumberPattern =new Regex("(" + strValidRealPattern +")|(" + strValidIntegerPattern + ")");

      IConvertible convertible1 = null;
      }
}

        foreach(char Char in strIn) {
程序中用Information.isnumeric("ddddd");

        {

    return Regex.IsMatch(value, @"^/d*[.]?/d*$");
//StringType.IsHexOrOctValue(text1, ref num2))
      int num2 = Value.Length;

b)

//----------------------------------------------------
    String strValidIntegerPattern="^([-]|[0-9])[0-9]*$";
            char ch1 = Value[num1];

      }

            if (inString[i] != '+' && inString[i] != '-')
        }
        else if (inString[i] == '.')
            long num2;
            }
            Result = double.Parse(Value, NumberStyles.Any, info2);
        {
      {
            {
            {
                  }
}
                  {
                  return DoubleType.TryParse(text1, ref num1);
        }
    return haveNumber;
            }
{
public static bool IsNumeric(object Expression)

private bool IsNumberic(string oText)

            return false;
                break;

复制代码 代码如下:

    for(int i=0;i    {
            }
      switch (TypCode)
      try
        if(ch[i]<48 || ch[i]>57)
            }
}

                continue;
      int num1;
    if(strIn=="") {
            {
            flag1 = double.TryParse(Value, NumberStyles.Any, info3, out Result);
        }
 

            case TypeCode.Int16:
      }
internal static bool TryParse(string Value, ref double Result)
            if (Expression is char[])
public static bool IsUnsign(string value)
        }

方案一：Try...Catch(执行效率不高)

      while (num1 < num2)
            }
            convertible1 = (IConvertible) Expression;
    }

        return false;
{

public bool IsNumber(String strNumber)
      {
                  }
      bool flag1;
      }
        {
                        i64Value = Convert.ToInt64(text1, 0x10);
            }
    Regex objTwoMinusPattern=new Regex("[0-9]*[-][0-9]*[-][0-9]*");
            flag1 = true;
    return Regex.IsMatch(value, @"^[+-]?/d*[.]?/d*$");
}

                  {

方案四：改写vb的IsNumeric源代码(执行效率不高)

            flag1 = false;
{
            case TypeCode.Single:
}
            return false;
      }
    return bolResult;
      {
}

{
            {
        }
                  if (ch1 == 'h')
internal static bool IsHexOrOctValue(string Value, ref long i64Value)
}

        else
internal static bool IsNumericTypeCode(TypeCode TypCode)
    inString = inString.Trim();
        objNumberPattern.IsMatch(strNumber);
{
      return false;

public static bool IsNumeric(string value)
      catch (FormatException)
                  return true;
            else
                return false;
        if (i > 20)
            {
      {
    {
        return true;
      return false;
            return false;
        else if (i == 0)
            haveNumber = true;
      return flag1;
{
    else {
    bool bolResult=true;
    ch=str.ToCharArray();
            else {
                  string text1 = StringType.ToHalfwidthNumbers(Value.Substring(num1 + 2));

复制代码 代码如下:

      {
                  }
      {

复制代码 代码如下:

            case TypeCode.Byte:

方案五：直接引用vb运行库(执行效率不高)

            case TypeCode.Double:

a)

{
    }
      {
{
      if (Expression is IConvertible)

using System;
using System.Text.RegularExpressions;

      catch (Exception)
        if (Char.IsNumber(inString[i]))
      NumberFormatInfo info2 = DecimalType.GetNormalizedNumberFormat(info3);
            case TypeCode.UInt16:
            if(char.IsNumber(Char))
            num1++;

public bool IsInteger(string strIn) {
      }
            case TypeCode.UInt32:
                  break;
            {
    char[] ch=new char[str.Length];
            }
                haveDot = true;
    String strValidRealPattern="^([-]|[.]|[-.]|[0-9])[0-9]*[.]*[0-9]+$";
                return false;

public static bool isNumeric(string inString)
            case TypeCode.SByte:

public bool isnumeric(string str)
    return true;
                  return true;
      }
}

复制代码 代码如下:

      bool flag1;
      TypeCode code1 = convertible1.GetTypeCode();
      if (convertible1 == null)
}
      Value = StringType.ToHalfwidthNumbers(Value, info1);
                  return false;
                  {
            }
                  return false;
            {
    {

方案三：遍历

c)

      if (info3 == info2)
    Regex objTwoDotPattern=new Regex("[0-9]*[.][0-9]*[.][0-9]*");
            if (!StringType.IsHexOrOctValue(text1, ref num2))
    {
            }

复制代码 代码如下:

      catch (Exception)
    return Regex.IsMatch(value, @"^[+-]?/d*$");

    }

        int var1=Convert.ToInt32 (oText);
      try

//主调函数
      string text1 = convertible1.ToString(null);
                  else if (ch1 == 'o')
    catch
                  Expression = new string((char[]) Expression);
      {
            {
// DoubleType.TryParse(text1, ref num1);
            case TypeCode.Int32:
            }
      {
                        throw new FormatException();
        }
                  else
{
      }
    }
}//子函数
                bolResult=false;
            {
                  double num1;
      return flag1;

以上就是C#判断一个String是否为数字类型的全部内容，推荐大家使用正则表达式的方法，比较简单且效率高。

            if (ch1 == '&')
public static bool IsInt(string value)
      {

b)

            flag1 = false;
      }
            if (haveDot)

//-----------------
      {

方案二：正则表达式(推荐)

    bool haveNumber = false;
        !objTwoMinusPattern.IsMatch(strNumber) &&